(y-2)^2+3(y+3)=y(y+2)+5y+8

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Solution for (y-2)^2+3(y+3)=y(y+2)+5y+8 equation: 



(y-2)^2+3(y+3)=y(y+2)+5y+8

We move all terms to the left:

(y-2)^2+3(y+3)-(y(y+2)+5y+8)=0

We multiply parentheses

(y-2)^2+3y-(y(y+2)+5y+8)+9=0



We calculate terms in parentheses: -(y(y+2)+5y+8), so:

y(y+2)+5y+8

We add all the numbers together, and all the variables

5y+y(y+2)+8

We multiply parentheses

y^2+5y+2y+8

We add all the numbers together, and all the variables

y^2+7y+8

Back to the equation:

-(y^2+7y+8)



We add all the numbers together, and all the variables

3y+(y-2)^2-(y^2+7y+8)+9=0

We get rid of parentheses

-y^2+3y+(y-2)^2-7y-8+9=0

We add all the numbers together, and all the variables

-1y^2-4y+(y-2)^2+1=0

We move all terms containing y to the left, all other terms to the right

-1y^2-4y+(y-2)^2=-1

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